Question

There are 3 consecutive even integers that have a sum of 6. What is the value of the least integer?

Answer 1

We can express this question as follows:

`n+(n+2)+(n+4)=6`

Now, we can sum the like terms (n's) and the integers in the previous expression. Then, we have:

`(n+n+n)+(2+4)=6=3n+6\Rightarrow3n+6=6`

Then, to solve the equation for n, we need to subtract 6 to both sides of the equation, and then divide by 3 to both sides too:

`3n+6-6=6-6\Rightarrow3n=0\Rightarrow n=(3)/(3)n=(0)/(3)\Rightarrow n=0_{}`

Then, we have that the three consecutive even integers are:

`0+2+4=6`

Therefore, the least integer is 0.