Question

An auto mechanic recommends that 3 ounces of isopropyl alcohol be mixed with a tankful of gas (14 gallons ) to increase the octane of the gasoline for better engine performance. At this rate, how many gallons of gas can be treated with a 16-ounce bottle of alcohol (You don’t need to translate or understand just solve the word problem please )

Answer 1

Let be "x" the number of gallons of gas that can be treated with a 16-ounce bottle of alcohol.

According to the information given in the exercise, 3 ounces of isopropyl alcohol should be mixed with 14 gallons of gas.

Then, you can set up the following proportion:

`(14)/(3)=(x)/(16)`

Now you have to solve for "x":

`\begin{gathered} (16)((14)/(3))=x \\ \\ (224)/(3)=x \\ \\ x\approx74.67 \end{gathered}`

Therefore, the answer is:

`\approx74.67\text{ }gallons`