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How much work is done on a medicine ball with a force of 29 newtons when you lift it 5 meters?

1 Answer

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Given data

*The given force is F = 29 N

*The given distance is s = 5 m

The formula for the work is done on a medicine ball is given as


W=F\mathrm{}s

Substitute the known values in the above expression as


\begin{gathered} W=(29)(5) \\ =145\text{ J} \end{gathered}

Hence, the work is done on a medicine ball is W = 145 J

User Liviu Mandras
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