Question

Triangle LMN is drawn with vertices at L(−2, 1), M(2, 1), N(−2, 3). Determine the image vertices of L′M′N′ if the preimage is rotated 90° clockwise. L′(1, 2), M′(1, −2), N′(3, 2) L′(−1, 2), M′(−1, −2), N′(−3, 2) L′(−1, −2), M′(−1, 2), N′(−3, −2) L′(2, −1), M′(−2, −1), N′(2, −3)

Answer 1

L'(1, 2), M'(1, -2), N'(3, 2)

Step-by-step explanation

The rule for rotating a point (x, y) 90° clockwise is,

`(x,y)\rightarrow(y,-x)`

So, the vertices of triangle LMN will be mapped to,

`\begin{gathered} L(-2,1)\rightarrow L^(\prime)(1,2) \\ M(2,1)\rightarrow M^(\prime)(1,-2) \\ N(-2,3)\rightarrow N^(\prime)(3,2) \end{gathered}`

Hence, the image has vertices L'(1, 2), M'(1, -2), N'(3, 2).