Question

Rathan thinks all factors of even numbers are even. Is Rathan correct or incorrect? He is correct because the product of 2 and any number is odd. He is correct because the product of two even numbers is even. He is incorrect because the product of an even number and an odd number is even. He is incorrect because the product of two odd numbers is odd.

Answer 1

C He is incorrect because the product of an even number and an odd number is even

Step-by-step explanation:

Answer 2

He is incorrect because the product of an even number and an odd number is even