Question

How do I simplify my answer of 42i^2+32i+6 when the original problem was (2-6i)(3-7i)

Answer 1

Given problem is

`(2-6i)(3-7i)`

Now,

`\begin{gathered} (2-6i)(3-7i)=42i^2-14i-18i+6 \\ =42i^2-32i+6 \end{gathered}`

We know that

`i^2=-1`

Using this face,

`\begin{gathered} 42i^2-32i+6=-42-32i+6 \\ =-32i-36 \end{gathered}`

Hence, the simplified form is

`-32i-36`