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What is the slope-intercept form of an equation of a line that passes through the point (0,-1) and is perpendicular to 5x-y=3?

User Beans On Toast
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1 Answer

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19 votes

Answer:

y = -1/5x - 1

Explanation:

Perpendicular lines slopes are negative reciprocals of each other.

Write the given equation in the slope-intercept form: y = mx + b

5x - y = 3

-y = -5x + 3

y = 5x - 3 multiply by -1

The slope of the given line is 5 ( the coefficient of the x-term).

The slope of the new equation will -1/5 (this is the negative reciprocal of 5).

Next find "b" using y = mx + b, the new slope -1/5 and the point (0, -1)

y = mx + b

-1 = -1/5(0) + b

-1 = 0 + b

-1 = b

Now write the equation y = -1/5x - 1

User Mculhane
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