Answer:
1.
The farmer needs to spread hay under all the squash plants. Write an expression, using x, that represents the amount of the area of the field just for the squash.
solution
area of rectangle is L x W,
let L =4x and and W = x
therefore Area (A) = 4x(x) = 4x2
2
The farmer needs a small fence for just around the potato patch. Write an expression, using x, that represents the perimeter of the part of the field just for potatoes. (simplify)
solution
parameter(P) = 2( L + W )
let L=x2 - 7x +12 and W = x +6
therefore
P = 2(x2 -7x +12 + x + 6)
= 2( x2 -6x + 18)
P = 2x2 -12x +36
3.
Challenge question! Write an expression, using x, that represents the perimeter of the entire garden, should the farmer want a bigger fence. (simplify)
solution
P= L1+L2+W1+W2
when
L1 = x + 6x +xy -1 = 7x +xy -1
L = 5x + 2 + x2 - 9 +x2 -7x + 12 = 2x2 5x + 2
w1 4x + 5x -2
w2 = xy + x 7
p = 7x +xy -1 + 2x2 5x + 2 + 4x + 5x -2 + xy + x 7
p = 2xy + 2x2 +16x +9
Explanation: