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Find the length and width of a rectangle with the following information belowArea = 2x^2 + 3x Perimeter = 6x + 6

User Urvish
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Length: L

Width: W

The area of a rectangle is:


A=L\cdot W

The perimeter of a rectangle is:


P=2W+2L

Given information:


\begin{gathered} A=2x^2+3x \\ \\ P=6x+6 \end{gathered}
\begin{gathered} L\cdot W=2x^2+3x \\ 2W+2L=6x+6 \end{gathered}

Solve L in the second equation (Perimeter):


undefined

User Gaurav Kumar Singh
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