1 Answer

Artur Soler · Answer 1 · 2023-09-13T18:41:06+0000

The length of a rectangle is 2cm greater than the width. The area is 80cm2. Find the length and width.

L=W+2

W=W

$\begin{gathered} A=L\cdot W \\ A=(W+2)\cdot W \\ A=W^2+2W \\ A=80\operatorname{cm} \\ Then, \\ 80=W^2+2W \\ W^2+2W-80=0 \end{gathered}$

$\Delta=4+320=324$
$\begin{gathered} W=\frac{-2\pm\sqrt[]{324}}{2}=(-2\pm18)/(2) \\ W_1=(-20)/(2)=-10 \\ W_2=(16)/(2)=8 \end{gathered}$

The width should be positive, therefore W=8

L=W+2

L=8+2=10

The length is L=10

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