Answer:
F = 1.36*10^-9
Step-by-step explanation:
The given equation is
![F=6.67\ast10^(-11)\ast((1.5\ast10^5)(8.5\ast10^2))/(2500^2)](https://img.qammunity.org/2023/formulas/physics/college/2adu20za142l5zxphoidn24fxfva92legr.png)
To calculate the value of F, you need to multiply 1.5*10^5 by 8.5*10^2 as follows:
![F=6.67\ast10^(-11)\ast(1.275*10^8)/(2500^2)](https://img.qammunity.org/2023/formulas/physics/college/hvol28fsw96cbihoimq4186sv7jpii8qe9.png)
Then, 2500² = 2500 x 2500 = 6.25 * 10^6, so replacing the value, we get:
![F=6.67\ast10^(-11)\ast(1.275\ast10^8)/(6.25\ast10^6)](https://img.qammunity.org/2023/formulas/physics/college/lpgj89pn1py91llksu4gjdemgqijce69te.png)
Now, we need to divide 1.275*10^7 by 6.25*10^6, so
![F=6.67\ast10^(-11)\ast(20.4)](https://img.qammunity.org/2023/formulas/physics/college/s3h2zbo6az8zkdsvk32xhqnlfkk4uapifd.png)
Finally, multiply 6.67*10^-11 by 20.4, so
![F=1.36\ast10^(-9)](https://img.qammunity.org/2023/formulas/physics/college/ilsf443atia82ofssvp6r9cz8clv2sgtsv.png)