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Answer this question and show me how to check it-example-1

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We write numbers that are very small or very large in standard form. Any number that we can write as a decimal number, between 1.0 and 10.0, multiplied by a power of 10, is said to be in standard form

Given that the length and thickness as


\begin{gathered} l=8*10^4 \\ t=5*10^(-6) \end{gathered}

The ordinary form of the wire is


\begin{gathered} l=8*10^4m=8*10000m=80000m \\ t=5*10^(-6)m=5*(1)/(1000000)m=0.000005m \end{gathered}

From the defination of standard form, taking the length, 8 is a number between 1.0 and 10.0 and 10⁴m is a power of 10.

Also, the width, 5 is a number between 1.0 and 10.0 and 10 ⁻⁶ is a power of 10.

Hence, the standard form of the length and thickness of the wire is

length = 8.0 x 10⁴m

thickness = 5.0 x 10 ⁻⁶m

User Junior Jiang
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