Question

Help me please what is the probability of all the letters?

Answer 1

Given:

• Number of male who survived = 338

,

• Number if female sho survived = 316

,

• Number f children who survived = 57

,

• Number of male who died = 1352

,

• Number of female who died = 109

,

• Number of children who died = 52

,

• Total number of people = 2224

Let's solve for the following:

(a). Probability of the passenger that survived:

`P(\text{survived)}=\frac{nu\text{mber who survived}}{total\text{ number if people }}=(711)/(2224)=0.320`

(b). Probability of the female.

We have:

`P(\text{female)}=\frac{\text{ number of females}}{total\text{ number }}=(425)/(2224)=0.191`

(c). Probability the passenger was female or a child/

`P(\text{female or child)}=(425)/(2224)+(109)/(2224)=(425+109)/(2224)=0.240`

(d). Probability that the passenger is female and survived:

`P(femaleandsurvived)=(316)/(2224)=0.142`

(e). Probability the passenger is female and a child:

`P(\text{female and child)=}(425)/(2224)*(109)/(2224)=0.009`

(f). Probability the passenger is male or died.

`P(male\text{ or died) = P(male) + }P(died)-P(male\text{ and died)}`

Thus, we have:

`P(\text{male or died)}=(1690)/(2224)+(1513)/(2224)-(1352)/(2224)=0.832`

(g). If a female passenger is selected, what is the probability that she survived.

`P(\text{survived}|\text{female)}=(316)/(425)=0.744`

(h). If a child is slelected at random, what is the probability the child died.

`P(died|\text{ child)=}(52)/(109)=0.477`

(i). What is the probability the passenger is survived given that the passenger is male.

`=(338)/(1690)=0.2`

ANSWER:

• (a). 0.320

,

• (b). 0.191

,

• (c). 0.240

,

• (d). 0.142

,

• (e). 0.009

,

• (f). 0.832

,

• (g) 0.744

,

• (h). 0.477

,

• (i) 0.2