Sara, this is the solution:
∛ 120a^4b^5c
Lets solve factor by factor:
∛ 120 = ∛ 8 * 15 = 2∛ 15
∛a^4 = a^4/3
∛b^5 = b^5/3
∛c (We can't simplify this factor)
In consequence, we have:
2a^(4/3) b^(5/3)∛ 15c
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