In this problem, want to find the equation of a line that will be parallel to a given function through a point.
Recall that parallel lines have the same slope.
We are given the line
![y=-1](https://img.qammunity.org/2023/formulas/mathematics/high-school/vwgcxbnu6slshz866yc5mzof7h9jqvl6lx.png)
and the point
![(-5,4)](https://img.qammunity.org/2023/formulas/mathematics/college/gatupxutdgf7vvephv9xg5ub4p38d84k2b.png)
Notice that the equations is technically in slope-intercept form, by the value of the slope will be 0:
![y=0x-1](https://img.qammunity.org/2023/formulas/mathematics/college/f30p307vobzchebvqv9w1dxe892y3x3cei.png)
Therefore, the slope of the line through (-5,4) will also be zero. We can use that information to find the equation.
Using the form
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
we can substitute the point and the slope to solve for b:
![\begin{gathered} 4=0(-5)+b \\ \\ 4=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p2m6a51ounio28b1h0ae9j818zcqckxzvn.png)
So, the equation of our line is:
![y=0x+4\text{ or }\boxed{y=4}](https://img.qammunity.org/2023/formulas/mathematics/college/dd75gxwurmcntxds7dbc0tk003yzx81v60.png)