Question

Find the value of x in the triangle shown below.42

Answer 1

Since we are dealing with a right triangle, we can use the Pythagorean theorem, shown below

`H^2=L^2_1+L^2_2`

In our case, H=4, L_1=2, L_2=x; then,

`4^2=2^2+x^2`

Solving for x,

`\begin{gathered} \Rightarrow x^2=16-4 \\ \Rightarrow x^2=12 \\ \Rightarrow x=\sqrt[]{12}=\sqrt[]{4\cdot3} \\ \Rightarrow x=2\sqrt[]{3} \end{gathered}`

The answer is x=2sqrt(3)