We are given the equation 7x+8=4x-10 and we want to find the value of x, such that the equality holds. To do so, we will start with the equation and the solve it for x. That is, we will apply mathematical operations on both sides of the equation, so we end up "ilosating" the x on one side of the equality sign. We start by
![7x+8=4x\text{ - 10}](https://img.qammunity.org/2023/formulas/mathematics/college/u4sufx2mks7wwzl4aaooy8u95jbikns56v.png)
First, we subtract 4x on both sides, so we get
![\text{ -10=(7x-4x)+8=3x+8}](https://img.qammunity.org/2023/formulas/mathematics/college/2xkf03axy1noi3b6dvyvcwansctyahbtlg.png)
Now, we subtract 8 on both sides, so we get
![3x=\text{ -10-8=-18}](https://img.qammunity.org/2023/formulas/mathematics/college/vtfgffm6pj1c3ag55z6fmhljq8y2i7hyy5.png)
Finally, we divide both sides by 3, so we get
![x=\frac{\text{ -18}}{3}=\text{ -6}](https://img.qammunity.org/2023/formulas/mathematics/college/se0x06ty6aaoecx8dro712u8d4g368l4un.png)
so x=-6.