Question

The owner of a recycling company wants to reduce his electrical consumption and costs. The electromagnet used in his operation uses 12 A of current, has 7000 loops and a lifting force of 9800 N. If the lifting force needs to remain the same but the owner would like to reduce the current to only 5 A, how many loops would the electromagnet have?

Answer 1

Given:

Current, I = 12 A

Loops, B = 7000

Force, F = 9800 N

Let's determine the loops if the force remains the same but the current redudces to 5A.

Apply the formula:

`F=(I* N)/(L)`

Let's solve for L.

`\begin{gathered} L=(I* N)/(F) \\ \\ L=(12*7000)/(9800) \\ \\ L=8.57\text{ m} \end{gathered}`

If the current reduces to 5 A, we have:

`\begin{gathered} N=(F* L)/(I) \\ \\ \text{Where I = 5 A} \\ \\ N=(9800*8.57)/(5) \\ \\ N=16800\text{ } \end{gathered}`

The number of loops the electromagnet would have is 16800 loops.