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How do I find the product of (10−11i) and its conjugate?

1 Answer

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Explanation:

Given - 10 - 11i

1st requirement - conjugate

Z = X + Yi

Change the sign between x & yi to find the conjugate of a complex

number.

Z = 10 + 11i

Now multiply the conjugate & the 1st complex number

=10-11i × 10+11i

= (10 × 10)+ (10× 11i)+ (-11i × 10) + (-11i × 11i)

Recall that i = √-1

= 100 + 110i - 110i + (-(-(11 × 11))...since √-1 × √-1 = -1.

= 100 + 121

= 221.

User Mangu
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