You have th following equation;

In order to find the solution to the previous equation, use the quadratic formula:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
In this case, a = 3, b = -5 and c = 1. By replacing these values into the quadratic formula, you obtain:
![\begin{gathered} x=\frac{-(-5)\pm\sqrt[]{(-5)^2-4(3)(1)}}{2(1)} \\ x=\frac{5\pm\sqrt[]{25-12}}{2}=\frac{5\pm\sqrt[]{13}}{2} \\ x=(5\pm3.60)/(2)=2.5\pm1.80 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ba6qvr617dcpjpkdrtwlkdur7t1y8f780x.png)
Hence, the solutions are:
x = 2.5 + 1.80 = 4.30
x = 2.5 - 1.80 = 0.70