Question

I need to the equation of a line as (-5,-3); slope = -3/5

Answer 1

To answer this question, we will use the following formula for the equation of a line that passes through (x₁,y₁), and has slope m:

`y-y_1=m(x-x_1)\text{.}`

Substituting (x₁,y₁)=(-5,-3) and m=-3/5 in the above formula we get:

`y-(-3)=-(3)/(5)(x-(-5))\text{.}`

Simplifying the above equation we get:

`\begin{gathered} y+3=-(3)/(5)(x+5), \\ y+3=-(3)/(5)x-(3)/(5)5, \\ y+3=-(3)/(5)x-3, \\ y+3-3=-(3)/(5)x-3-3, \\ y=-(3)/(5)x-6. \end{gathered}`

Answer:

`y=-(3)/(5)x-6\text{.}`