Question

joanne graphed a linear funtion with a slope of -4 passing through 0,-2 nick graphed the function y=-2x - 4

Answer 1

Step-by-step explanation:

The slope-intercept form of the equation of a line can be written as;

`y=mx+b`

where m = slope of the line

b = y-intercept of the line

So if Joanne graphed a linear function with a slope(m) of -4 passing through (0, -2), let's go ahead and determine the y-intercept of the line as shown below;

`\begin{gathered} -2=-4(0)+b \\ -2=b \\ b=-2 \end{gathered}`

Therefore, the equation of line will be y = -4x - 2 as graphed below;

Given Nick's function as y = -2x - 4, combining both graphs, we'll have the below;

The red line is Joanne's line while the blue line is Nick's line.

We can see from the above graph of both lines that Joanne's line intersects the y-axis above Nick's line's