162k views
3 votes
Written as a percent, what is the probability of getting an odd number on a spinner with 5 equal parts numbered 1 to 5?A.20%B.40%C.60%D.80%

1 Answer

2 votes

Given:

There are given that the spinner with 5 equal parts numbered 1 to 5.

Step-by-step explanation:

In the given spinner, there are given the number: 1, 2, 3, 4, 5.

Now,

From all the given numbers, there are 3 odd numbers: 1, 3, and 5.

So,

From the probability:


P=\frac{Total\text{ number of odd numbers in the given spinner}}{Total\text{ numbers on the spinner}}

Then,


\begin{gathered} P=(3)/(5) \\ P=0.6 \end{gathered}

Now,

For the percentage:


\begin{gathered} P=0.6*100\% \\ P=60\% \end{gathered}

Final answer:

Hence, the correct option is C.

User MishaF
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories