(a)
We have five pulse rates randomly selected with a mean of 74.4 beats per minute. We have four pulse rates given. We let x be the value of the fifth pulse rate. We have n equals 5 here since we have sample space of 5. We illustrate the mean of the pulse rates as
![\begin{gathered} \operatorname{mean}=(\sum x)/(n) \\ \\ 74.4=(84+66+79+57+x)/(5) \end{gathered}]()
Let's solve for the value of x. We have
![\begin{gathered} 74.4=(286+x)/(5) \\ 286+x=(74.4)\cdot5 \\ 286+x=372 \\ x=372-286 \\ x=86 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/hybf4wri4rgvscgh2xui4h771128ohejjg.png)
Hence, the missing value is equal to 86.
Answer: 86
(b) The number of degrees of freedom is calculated using the equation
![\text{Degrees of freedom}=n-1](https://img.qammunity.org/2023/formulas/mathematics/high-school/sqzefwtuhg3yks0w3tyvov3n707uwy8jtt.png)
We already identified that the sample space n is equal to 5. Hence, the degrees of freedom is equal to
![\text{Degrees of freedom}=5-1=4](https://img.qammunity.org/2023/formulas/mathematics/high-school/py65vvv37r6pvxlz0wlnqjs1razjvcovhs.png)
Answer: 4