103,659 views
5 votes
5 votes
mr dudzic has above ground swimming pool thatbis a circular cylinder. the diameter of the pool is 25 ft. and the height isb4.5 ft. in order to open he needs to shock it with chlorine. if one gallon of liquid chlorin treats 3000 gallons of water, how many full gallons will he need to buy. (1 foot^3=7.48 gallons)

User Oz Cohen
by
2.9k points

1 Answer

2 votes
2 votes

The volume of the cylinder is


V=\pi\text{ }* r^2* h

The diameter of the cylinder is 25 feet, then

The radius of it = 1/2 x diameter


r=(1)/(2)*25=12.5ft

Since the height is 4.5 ft

Substitute them in the rule above


\begin{gathered} V=3.14*(12.5)^2*4.5 \\ V=2207.8125ft^3 \end{gathered}

Now we will change the cubic feet to gallons


\because1ft^3=7.48\text{ gallons}

Then multiply the volume by 7.48 to find the number of gallons


7.48*2207.8125=16514.4375gallons

Now let us divide the number of gallons by 3000 to find how many gallons of liquid chlorin he needs to buy


(16514.4375)/(3000)=5.5048125

Then he has to buy 6 full gallons

User Sheldon Ross
by
3.4k points