Answer:
The system of equations is:
• C(x)=2400+60x
,
• R(x)=120x
The number of bicycles to break even = 40
Explanation:
Let the number of bikes sold = x
• The operating cost of the store per month = $2400
,
• Cost Price Per bike = $60
Thus, the total monthly cost for the store:
![C(x)=2400+60x](https://img.qammunity.org/2023/formulas/mathematics/high-school/fnmsfstv2rtc4w93bacr3p3uzqvv67h51s.png)
Next, the average selling price of each bicycle is $120, therefore, the monthly revenue of the store:
![R(x)=120x](https://img.qammunity.org/2023/formulas/mathematics/high-school/eccwssihdjb2cg28bk5nq69yl23nc2jhrd.png)
The store breaks even when the cost equals its revenue.
![\begin{gathered} R(x)=C(x) \\ 120x=2400+60x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1b1bmmou7ef2trsntq09v1obog8s7zzydq.png)
We then solve for x:
![\begin{gathered} \text{ Subtract 60x from both sides of the equation} \\ 120x-60x=60x-60x+2400 \\ 60x=2400 \\ \text{ Divide both sides of the equation by 60} \\ (60x)/(60)=(2400)/(60) \\ x=40 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tnb1skd66tl6rn7i4scgjgndpn9yer32di.png)
The store must sell 40 bicycles in order to break even.