Question

Two ships left a port at the same time. Onetravelled due north and the other due eastat average speeds of 25.5 km/h and 20.8 km/h,respectively. Find their distance apart

Answer 1

Given:

Two ships left a port at the same time.

One travelled due north at an average speed of 25.5 km/h

And the other ship was due east at average speeds of 20.8 km/h

We will find their distance apart using the Pythagorean theorem.

The distance = Speed * Time

Let the time = t

So, the distance of the first ship = 25.5t

And the distance of the second ship = 20.8t

So, the distance between the ships (d) will be as follows:

`\begin{gathered} d^2=(25.5t)^2+(20.8t)^2 \\ d^2=1082.89t^2 \\ \\ d=√(1082.89t^2) \\ d=32.907t \end{gathered}`

So, the answer will be:

The distance in terms of time = 32.907t

We will find the distance when t = hours

So, distance = 164.54 km