Question

Does the point (3,-1) lie on the circle (x + 1)2 + (y - 1)1)2 = 16?no; the point is not represented by (h, k) in the equationyes; when you plug the point in for x and y you get a true statementno; when you plug in the point for x and y in the equation, you do not get a trueyes; the point is represented by (h, k) in the equation

Answer 1

We are given an equation of a circle and a point. We are then asked to find if the point lies on the circle. The equation of the circle and the point is given below

`\begin{gathered} \text{Equation of the circle} \\ (x+1)^2+(y-1)^2=16 \\ \text{Given point =(3,-1)} \end{gathered}`

To find if the point lies in the circle, we can use the simple method of substituting the coordinates into the equation of the circle.

This can be seen below:

`\begin{gathered} (3+1)^2+(-1-1)^2=16 \\ 4^2+(-2)^2=16 \\ 16+4=16 \\ \therefore20\\e16 \end{gathered}`

Since 20 cannot be equal to 16, this implies that the point does not lie on the circle.

ANSWER: Option 3