Question

Apassenger in a drops a and it freely from rest to the groundWhat is the speed of the ball a distance of 20 massuming the acceleration due to gravity equal to 9.01 m/s ^ 2

Answer 1

Given data

*The given initial speed is u = 0 m/s

*The given distance is s = 20 m

*The value of the acceleration due to gravity is g = 9.01 m/s^2

The formula for the final speed of the ball at a distance of 20 m is given by the kinematic equation of motion as

`v^2=u^2+2gs`

Substitute the known values in the above expression as

`\begin{gathered} v^2=(0)^2+2(9.01)(20) \\ v^2=\text{36}0.04 \\ v=18.98\text{ m/s} \end{gathered}`

Hence, the speed of the ball at a distance of 20 m is v = 18.98 m/s