We must first check the valence number of the sulfur in the sulfate ion. In this ion, the valence number is +6 and we have 4 bonded oxygens.
![\begin{gathered} S^(+6)\lbrack O^(-2)_4\rbrack^(-8) \\ SO^(-2)_4 \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/yv5iumo5chq0637yv9epsifqt34jk165ud.png)
The Lewis structure of the sulfate ion is as follows:
We have six bonding in the molecule. So the answer will be B. six bonding and no lone pairs of electrons.