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Starting with a gas of N2 in a balloon of temperature 148.5°C and volume 241.8mL, what is its final volume if you cool it to -96.4°C?

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Answer

101.3 mL

Step-by-step explanation

Given:

The initial temperature, T₁ = 148.5 °C = (148.5°C + 273) = 421.5 K

The initial volume, V₁ = 241.8 mL

Final temperature, T₂ = -96.4 °C = (-96.4°C + 273) = 176.6 K

What to find:

The final volume of the gas.

Step-by-step solution:

The final volume, V₂ of the gas can be calculated using Charle's law formula.


\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ \\ \Rightarrow V_2=(V_1* T_2)/(T_1)=(241.8mL*176.6K)/(421.5K)=\frac{42701.88\text{ }mL}{421.5} \\ \\ V_2=101.3\text{ }mL \end{gathered}

The final volume of the gas is 101.3 mL

User Eric Pruitt
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