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What is the surface are of this cone rounded to the nearest tenth of a square foot?

What is the surface are of this cone rounded to the nearest tenth of a square foot-example-1
User Lordzuko
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1 Answer

4 votes

ANSWER


282.7ft^2

Step-by-step explanation

Recall, the formula for calculating the surface area of a cone is;


A=\pi r^2+\pi r√(r^2+h^2)

Given;


\begin{gathered} radius(r)=5 \\ height(h)=12 \end{gathered}

Substitute the values into the formula;


\begin{gathered} A=\pi 5^2+\pi 5√(5^2+12^2) \\ =\pi5^2+\pi5√(25+144) \\ =25\pi+5\pi*13 \\ =25\pi+65\pi \\ =90\pi \\ =90*3.14 \\ =282.74 \\ \cong282.7 \end{gathered}

User Yao
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