Question

Sara’s dogsMorning: 39, 21, 12, 27, 23, 19, 31, 36, 25Afternoon: 15, 51, 8, 16, 43, 34, 27, 11, 8, 39Comparing the morning and afternoon groups Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds.

Answer 1

Answer;

Medain for morning is 25

Median for evening is 21.5

Explanation;

Here, we want to create frequency tables for each of the given groups

We start with the morning group

The frequency table for it is as follows;

Now, we proceed to the afternoon group

We have this as follows;

Lastly, we will want to get the median value of both groups

To do this, we need to re-arrange the values in the data set in ascending or descending order

For the purpose of this solution, we shall be using the ascending order mode. Then from here, we pick out the middle value

For the morning group, we have;

12, 19,21, 23,25,27,31,36,39

Since the numbers are 9, the middle number will be the 5th number since it leaves equal spread of values on the left and right

Thus, we have the median value as 25

The afternoon set, we have it as;

8,8,11,15,16,27,34,39,43,51

We proceed to choose the mid 5th values comig from both ends

We have this as;

We have these values as; 16 and 27

We add these and divide by 2

We have this as;

`(16+27)/(2)\text{ = 21.5}`