Question

- What is the perimeter of a right triangle witha hypotenuse that measures 6 square root 5 cm and onealeg that measures 4 square root 5 cm

Answer 1

`\begin{gathered} \text{From Pythagoras theorem,} \\ (6\sqrt[]{5})^2=(4\sqrt[]{5})^2+m^2 \\ 36(5)=16(5)+m^2 \\ 180=80+m^2 \\ m^2=180-80 \\ m^2=100 \\ m=\sqrt[]{100} \\ m=10\text{ cm} \end{gathered}`