Question

There is $1.90 in a jar filled with quarters, dimes, and nickels. There are 2 more quarters than dimes and there are 2 more nickels than quarters. How many of each coin are there? quarters dimes [ ) nickels Enter the number that belongs in the green box.

Answer 1

Answer:

5 quarters, 3 dimes, 7 nickels

Explanations:

Let the number of quarters in the jar = q

Let the number of dimes in the jar = d

Let the number of nickels in the jar = n

1 quarter = $0.25

1 dime = $0.1

1 nickel = $0.05

The jar is filled with quarters, dimes, and nickels, totaling $1.90

This can be represented mathematically as:

0.25q + 0.1d + 0.05n = 1.90.........(1)

There are two more quarters than dime:

q = d + 2..............(2)

There are two more nickels than quarters

n = q + 2..............(3)

make d the subject of the formula in equation (2)

d = q - 2............(4)

Substitute equations (3) and (4) into equation (1)

0.25q + 0.1(q - 2) + 0.05(q + 2) = 1.90

0.25q + 0.1q + 0.05q - 0.2 + 0.1 = 1.90

0.4q - 0.1 = 1.90

0.4q = 1.90 + 0.1

0.4q = 2.0

q = 2.0/0.4

q = 5

n = q + 2

n = 5 + 2

n = 7

d = q - 2

d = 5 - 2

d = 3

There are 5 quarters, 3 dimes, 7 nickels