We have to calculate the volume of the cone.
The volume of the cone is 1/3 of the area of the base times the height.
As the base has diameter D = 16 yd, we can calculate the area of the base as:
![\begin{gathered} A_b=(\pi D^2)/(4) \\ A_b\approx(3.14*16^2)/(4) \\ A_b\approx(3.14*256)/(4) \\ A_b\approx200.96 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6y6evgmbqtash65pvdulrrgcr85horn35g.png)
Knowing the height is h = 14 yd, we then can calculate the volume as:
![\begin{gathered} V=(1)/(3)A_bh \\ V=(1)/(3)*200.96*14 \\ V\approx937.81 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5hv5eg7gg2zc6udntaai9s1ch0ugm8inuf.png)
Answer: the volume is 937.81 cubic yards.