Question

find the pressure increase in a fluid when a force of 25 N is exerted on a closed syringe where the piston radius is 2 cm.

Answer 1

Given:

• Force, F = 25 N

,

• Radius, r = 2 cm

Let's find the pressure increase.

To find the pressure increase, apply the formula:

`\Delta P=(Force)/(Area)=(F)/(\pi r^2)`

Where:

F = 25 N

r is the radius in meters = 2 cm

P is the pressure

Convert the radius from cm to meters.

Where:

100 cm = 1 m

2 cm = 2 /100 = 0.02 m

Hence, we have:

`\begin{gathered} \Delta P=(25)/(\pi(0.02)^2) \\ \\ \Delta P=(25)/(\pi(0.0004)) \\ \\ \Delta P=(25)/(0.00125664) \\ \\ \Delta P=19894.4\text{ Pa}\approx1.99*10^4\text{ Pa} \end{gathered}`

Therefore, the pressure increase is 1.99 x 10⁴ Pa.

ANSWER:

1.99 x 10⁴ Pa