Question

A gas has a volume of 1.82 L at-30°C and 131 kPa. At what temperature would the gasoccupy 1.3 L at 233 kPa?Answer in units of°C.

Answer 1

To solve this problem we can use the Ideal gas law:

`(P_1\cdot V_1)/(T_1)=(P_2V_2)/(T_2)`

The problem give us de following information:

P1= 131kPa

V1=1.82L

T1=-30°C= 243.15 K

P2= 233 kPa

V2= 1.3L

Then we just have to solve for T2 and use the information provided:

`T_2=(P_2\cdot V_2)/(P_1\cdot V_1)\cdot T_1=\frac{233\text{ kPa}\cdot1.3L}{131kPa\cdot1.82L}\cdot243.15K=308.91K=35.76°C`

Then the answer is T2=35.76°C