Question

I'm not sure how to do this. This is a long one that's why.

Answer 1

We have the following:

For the area surface:

`As=2\pi rh`

repacing:

r = 1.5 in

h = 7 in

`\begin{gathered} As=2\cdot3.14\cdot1.5^{}\cdot7 \\ As=65.94 \end{gathered}`

The answer is 65.9 in^2

For volume:

`\begin{gathered} V=\pi r^2h \\ V=3.14\cdot1.5^2\cdot7 \\ V=49.455 \end{gathered}`

The answer is 49.5 in^3