SOLUTION
Given the question in the question tab, the following are the solution steps to answer the question.
STEP 1: Write the formula for total surface area of cuboid

STEP 2: Get the dimension of the sides

STEP 3: Substitute the dimensions into the formula to get the value of x
![\begin{gathered} 2(lb+bh+lh)=88 \\ By\text{ substitution,} \\ 2((x\cdot2x)+(2x\cdot3x)+(x\cdot3x))=88 \\ \Rightarrow2(2x^2+6x^2+3x^2)=88 \\ \text{Divide both sides by 2} \\ \Rightarrow(2(2x^2+6x^2+3x^2))/(2)=(88)/(2) \\ \Rightarrow2x^2+6x^2+3x^2=44 \\ 11x^2=44 \\ \text{Divide both sides by 11} \\ (11x^2)/(11)=(44)/(11) \\ x^2=4 \\ x=\sqrt[]{4}=2 \\ x=2m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/71mhf5cknnxu6refyzku9u9m512mrlq1wm.png)
STEP 4: Get the other dimensions

Hence, the dimensions are:
