First, rewrite all the mixed fractions as impropper fractions:
![\begin{gathered} 10(1)/(2)=10*(2)/(2)+(1)/(2)=(20)/(2)+(1)/(2)=(21)/(2) \\ \\ 7(1)/(2)=7*(2)/(2)+(1)/(2)=(14)/(2)+(1)/(2)=(15)/(2) \\ \\ 2(1)/(5)=2*(5)/(5)+(1)/(5)=(10)/(5)+(1)/(5)=(11)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/trshyts3rqnkw33g7h3r9h00cgkmgkm2f7.png)
Next, multiply the rate of chocolate production over time by the the operating time of the machines to find the total amount of pounds of chocolate frogs produced in one day:
![7(1)/(2)*2(1)/(5)=(15)/(2)*(11)/(5)=(15*11)/(2*5)=(3*11)/(2)=(33)/(2)=16(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/a8aqtlv5mj6akfb9fs45nq4g1f8cin7ubx.png)
Then, the chocolate factory can produce 16 1/2 pounds of chocolate frogs per day.
Since 16 1/2 is greater than 10 1/2, then the chocolate factory will meet their goal with the total being over 10 1/2 pounds of chocolate frogs produced.