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Write a quadratic function whose graph passes through (3,6) and has the vertex (-2,4) what is the value of Y

User Zord
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The representation of a quadratic eqauation in vertex form is


y=a(x-k)^2+h

The given vertex is,


(k,h)=(-2,4)

And the given point through which the graph passes is,


(x,y)=(3,6)

Substitute the values in the formula of quadratic equation.


\begin{gathered} 6=a(3-(-2))+4 \\ 6=a(3+2)+4 \\ 6=5a+4 \\ 5a=6-4 \\ 5a=2 \\ a=(5)/(2) \end{gathered}

Hence, the equation in vertex form will be,


\begin{gathered} y=(5)/(2)(x-(-2))+4 \\ y=(5)/(2)(x+2)+4 \end{gathered}

User Delimiter
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