Question

Question 1. Write the equation of the line that goes through the points (-2,1) and (4,2).

Answer 1

Slope-intercept equation:

y=mx+b

Where:

m= slope

b=y- intercept

Point 1 = (x1,y1) = (-2,1)

Point 2 = (x2,y2)= (4,2)

First, find the slope by applying the formula:

`m=\text{ }(y2-y1)/(x2-x1)=(2-1)/(4-(-2))=(1)/(6)`

Now we have:

y=1/6x+b

Replace x,y by a point ( for example point 1 (-2,1)) and solve for b:

1 = 1/6 (-2) +b

1= -1/3 +b

1+1/3 = b

b= 4/3

Final equation:

y= 1/6x+4/3