Question

WXYZ is a kite. Use the figure below to fill in the blanks below.

Answer 1

We can assume the kite is simetrycal along line WY, as such

`ZW=XW=10`
`m\angle\text{XSW}=90`

because the diagonals of a kite are perpendicular.

Since m∠XSW is 90°, triangle WSX is a right triangle. Thus

`m\angle WXZ=m\angle WXS=180-90-46=44`

By the symmetry we discussed earlier,

`m\angle WYZ=m\angle WYX=18`

And finally

`m\angle XYZ=m\angle WYZ+m\angle WYX=18+18=36`