Question

A gas occupies a constant volume at 35.0 celsius and 97 kPa. What is the pressure of the gas when the temperature is increased to 75 celsius?

Answer 1

For this question we are going to use Gay-Lussac's Law, which is an experimental gas law that shows the relationship between temperature and pressure in a gas. The formula is:

P1/T1 = P2/T2

We have:

P1 = 97 kPa

T1 = 308 K, we need to use Kelvin

P2 = ?

T2 = 348 K

Now we add these values into the formula:

97/308 = P2/348

0.315 = P2/348

P2 = 109.6 kPa, this will be new pressure