![\begin{gathered} p=s^2+9s-142 \\ \text{ Substiyute }p\text{ = 2000 into the equation above} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/prucwf62dau6254pcz5veovu2d4pxrkqvg.png)
![\begin{gathered} 2000=s^2+9s-142 \\ s^2+9s-142-2000=0 \\ s^2+9s-2142=0 \\ =s^2+51s-42s-2142=0 \\ =s(s+51)-42(s+51)=0 \\ =(s+51)(s-42)=0 \\ s+51=0\text{ or s-42=0} \\ s=-51\text{ or s = 42} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/37qkkyrhiicogcjl81f46ljcr34o510z3b.png)
But cannot be negative, hence s= 42. This implies that 42 shirts will be sold to make a profit of exactly $2000.
To earn a profit of more than $2000, then s must be greater than 42
This makes the answer to be s > 42
The correct answer is the second option