The formula for Final Amount, A after compounding for n period of times is given by
![A=p(1+(r)/(100))^n](https://img.qammunity.org/2023/formulas/mathematics/college/rde38946af7uoszze470jjw5f6zf8g86rb.png)
Where A = amount
p= principal
r = rate (in %)
n = number of compounding periods
From the question.
A=21,000, p = ?, r=6, n = 3 x 2 = 6
![\begin{gathered} 21000=p(1+(6)/(100))6 \\ \\ 21000=p(1+0.06)^6 \\ 21000=p(1.06)6 \\ 21000=p(1.41852) \\ 21000=1.41852p \\ p=(21000)/(1.41852) \\ p=14,804.17 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/g56snyi9ils7zkhudtw1ny7kvk5j2yjrfh.png)
The amount that must be deposited at the beginning is 14,804.17