Question

Please help me with this!

Answer 1

The balloon goes 25 m east in first 10 s.

Then the wind blows the balloon 35 m west in 8 s.

a

The balloon travels 25 m in 10s.

b

the balloon travels a distance 35 m in next 8 s.

c

thhe total distance travelled by the balloon is,

`\begin{gathered} d=25+35 \\ =60\text{ m} \end{gathered}`

d

Average speed in 10 s is,

`\begin{gathered} s=(25)/(10) \\ =2.5\text{ m/s} \end{gathered}`

e

The average speed in next 8 s is,

`\begin{gathered} s_8=(35)/(8) \\ =4.37\text{ m/s} \end{gathered}`

f

the average speed for the entire trip is,

`\begin{gathered} s_(av)=(25+35)/(10+8) \\ =3.33\text{ m/s} \end{gathered}`

g

displacement during the first 10 s is.

`d_1=(25m)\hat{i}`

h.

displacement during next 8 s is,

`d_2=(-35m)\hat{i}`

i

The total displacement is,

`\begin{gathered} d_1+d_2=(25-35)\hat{i}_{} \\ =-(10m)\hat{i} \end{gathered}`

j

the average velocity in 10 s is,

`\begin{gathered} v_1=(25m)/(10)\hat{i} \\ =(2.5m)\hat{i} \end{gathered}`

k

The average velocity in 8 s is,

`\begin{gathered} v_2=\frac{-35\text{ m}}{8\text{ s}}\hat{i} \\ =-(4.37m)\hat{i} \end{gathered}`

l

The average velocity entire the whole trip is,

`\begin{gathered} v_(av)=(d_1+d_2)/(18) \\ =\frac{-10m\hat{i}}{18\text{ s}} \\ =-(0.55\hat{m/s)i} \end{gathered}`