Question

I need help with this question can you please help me

Answer 1

Given the following question:

`\begin{gathered} x^2+3x-5=0 \\ \text{ Convert using the quadratic formula:} \\ x^2+3x-5=0=x_(1,\:2)=(-3\pm√(3^2-4\cdot\:1\cdot\left(-5\right)))/(2\cdot\:1) \\ x_(1,\:2)=(-3\pm √(3^2-4\cdot \:1\cdot \left(-5\right)))/(2\cdot \:1) \\ \text{ Solve} \\ 3^(2)-4*1(-5) \\ 1*-5=-5 \\ 3^2-4*-5 \\ 3^2=3*3=9 \\ =29 \\ =√(29) \\ x_(1,\:2)=(-3\pm √(29))/(2\cdot \:1) \\ \text{ Seperate the solutions:} \\ x_1=(-3+√(29))/(2\cdot \:1) \\ x_2=(-3-√(29))/(2\cdot\:1) \\ \text{ Simplify} \\ 2*1=2 \\ x=(-3+√(29))/(2) \\ x=(-3-√(29))/(2) \end{gathered}`

Your answers are the first and second options.