The point of the problem is to remember the cosine relation. It says, in this case, that
![\cos (?)=\frac{\text{adjacent side}}{Hypotenuse}\Rightarrow\begin{cases}\text{adjacent side}=6 \\ \text{Hypotenuse}=13\end{cases}\Rightarrow\cos (?)=(6)/(13)](https://img.qammunity.org/2023/formulas/mathematics/college/5xrr79lepia63jd2dwtb804f9gbx97dqm3.png)
Converting the last equation by the inverse function, we get
![?=\cos ^(-1)((6)/(13))\approx62.5](https://img.qammunity.org/2023/formulas/mathematics/college/4cni2t3ht8b17d2j75lrhx665x9wjmr724.png)
For the first decimal place (5) equals 5, and by the rounding rule to the nearest degree, we get 63. The answer is A.